50x^2+15x-90=0

Solution for 50x^2+15x-90=0 equation:

50x^2+15x-90=0

a = 50; b = 15; c = -90;
Δ = b2-4ac
Δ = 152-4·50·(-90)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-135}{2*50}=\frac{-150}{100}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+135}{2*50}=\frac{120}{100}
=1+1/5
$